Ask Question
20 March, 21:59

A sine wave is offset 1/9 cycle with respect to time 0. What is its phase in degrees and radians? Which simple signal has a wider bandwidth, a sine wave with a frequency of 200 Hz or a sine wave with a frequency of 500 Hz?

+5
Answers (1)
  1. 21 March, 01:01
    0
    A.) Phase in degree = 40°; phase in radian

    B.) Bandwidth is the same.

    Explanation:

    1 complete cycle = 360°

    Therefore, 1/9 of a cycle:

    Phase in degree;

    (1/9) * 360° = 40°

    Phase in radian:

    40 * (2π/360)

    80π/360

    = 0.222πrad

    0.698rad

    In simple terms, A bandwidth could be explained as the difference between the upper and lower frequencies of the signal. However, the signal described above is a simple signal with no upper or lower frequency boundary.

    hence, the bandwidth is assumed to be the same.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A sine wave is offset 1/9 cycle with respect to time 0. What is its phase in degrees and radians? Which simple signal has a wider ...” in 📙 Computers & Technology if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers