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16 March, 06:25

Alex needs 80 / text{ cm}80 cm80, start text, space, c, m, end text of thread for a sewing project. The thread is on a spool with a circumference of 10 / text{ cm}10 cm10, start text, space, c, m, end text. How many times must Alex unwind the spool to get the length of thread he needs

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  1. 16 March, 08:17
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    Given Information:

    Alex needs 80 cm of thread for a sewing project.

    Thread is on a spool of 10 cm circumference

    Required Information:

    How many times Alex has to unwind the spool?

    Answer:

    8 times

    Explanation:

    According to the given data the circumference which is basically the outer length of the spool is 10 cm so that means 1 unwind is equal to 10 cm of thread.

    We need 80 cm of thread so we can write

    10x = 80

    Where x is the number of times to unwind the thread.

    x = 80/10 = 8

    Therefore, Alex has to unwind the spool 8 times to get the 80 cm of thread.
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