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23 February, 15:19

Consider the following method:

public static void doStuff (int a[], int b) {

if ( / * Missing Code * / ) {

for (int i = b; i < a. length; i++) {

a[i] = a[i] * 2;

}

}

}

What could be used to replace / * Missing Code * / so that there is no out of bounds exception?

a. b < a. length

b. b > 0 b < a. length

c. b > 0 && b < = a. length

d. b > = 0 || b < a. length

e. b > = 0 && b < a. length

+2
Answers (1)
  1. 23 February, 15:50
    0
    e. b > = 0 && b < a. length

    Explanation:

    Array indices in java begin at 0 and go up to number n-1, where n is the length of the array.

    Note: a. length returns the length of the array. We can assume the array length to be n for this case.

    Option a is incorrect since b can be less than 0, which causes an out of bounds exception.

    Option b is incorrect because two comparison statements are separated by a boolean operator, therefore it will cause a syntax error.

    Option c is incorrect because if b = a. length, this means that i will begin from nth index of the array, where as array indices only range from 0 to n-1 as mentioned earlier.

    Option d is incorrect because it uses the || (or) operator. This means that only one condition of the two given has to be true. Suppose if b is negative, this will cause b > = 0 to be false. However, since array length can never be negative, b < a. length will always be True, hence we can have an out of bounds exception in this case.
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