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16 June, 23:28

Which function grows faster: N log N or N1+ε / log N, ε > 0?

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  1. 17 June, 01:18
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    N logN grows faster.

    Explanation:

    In N1+∈/N logN logN is the denominator. So this term is constantly getting divided by logN while in N logN there is no term in the division and for N > 2 log N will be > 1. So N logN will gorw faster. Since ∈ is greater than 0 So the numerator will be greater than N but it will not grow as fast as N logN.
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