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31 May, 18:50

What is displayed on the console when running the following program?

public class Test {

public static void main (String[] args) {

try {

p ();

System. out. println ("After the method call");

}

catch (NumberFormatException ex) {

System. out. println ("NumberFormatException");

}

catch (RuntimeException ex) {

System. out. println ("RuntimeException");

}

}

static void p () {

String s = "5.6";

Integer. parseInt (s); / / Cause a NumberFormatException

int i = 0;

int y = 2 / i;

System. out. println ("Welcome to Java");

}

}

A. The program displays NumberFormatException.

B. The program displays NumberFormatException followed by After the method call.

C. The program displays NumberFormatException followed by RuntimeException.

D. The program has a compile error.

E. The program displays RuntimeException.

+1
Answers (1)
  1. 31 May, 19:49
    0
    The answer is "Option A"

    Explanation:

    In the given java code, a class "Test" is defined, inside the main method try and catch block is used, inside the try block method "p () " is called, that print a message. in this block two catch block is used, that works on "NumberFormatException" and "RuntimeException". In the method "p" declaration, a string variable "s" is defined, that holds double value, that is "5.6", and converts its value into the wrong integer, and other wrong option can be described as follows:

    In option B, it is wrong, it is not followed by after call method. In option C, It is not followed by runtime exception, that's why it is incorrect. Option D and Option E both were wrong because they can't give run time and compile-time error.
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