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9 July, 12:20

Write a Python function LetterGame () that repeatedly asks the user to input a letter. The function is to count the number of vowels the user entered. The function should stop if the user enters a digit (0-9). a) Use a while-loop and in the while loop ask the user to input a letter or to input a digit to stop. b) Check if the user entered a vowel (if command is your friend) c) If the user entered a vowel increase the counter by one d) If the user entered a digit, output the number of letters the user entered and the number and percentage of vowels among them. e) Call the function. Expected output: You entered 10 letters, 2 of which were vowels. The percentage of vowels was 20%.

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  1. 9 July, 14:06
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    def LetterGame ():

    vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]

    count1 = count2 = 0

    while True:

    choice = input ("Enter a letter / digit to stop: ")

    if choice. isdigit ():

    break

    elif choice. isalpha ():

    count1 + = 1

    if choice in vowels:

    count2 + = 1

    print ("You entered " + str (count1) + " letters, " + str (count2) + " of which weere vowels.")

    print ("The percentage of vowels was " + str (count2 / count1 * 100) + "%")

    LetterGame ()

    Explanation:

    Create a function called LetterGame

    Inside the function:

    Create a list of vowels

    Initialize count1, counts the total letters, and count2, counts the vowels

    Initialize a while loop that iterates until the specified condition is met in the loop

    Get the input from the user. If it is a digit, stop the loop. If it is an alphabet, increase the count1 by 1, and also check if it is a vowel. If it is a vowel, increment the count2 by 1

    When the loop is done, print the required information

    Finally, call the function
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