For a surface to exist, it must have I closed-loop AND be coplanar.

True

False

Question

Computers & Technology

Cheddar

29 July, 19:14

For a surface to exist, it must have I closed-loop AND be coplanar.

True

False

+3

Answers (1)

Know the Answer?

Nathaly Parks · Answer 1

False.

Explanation:

I will try to explain by presenting a contradiction to the given statement. Let us consider the surface of a sphere (a ball is a sphere). While it has a closed loop surface it is not coplanar. In fact, a sphere exists in 3d and its surface can not lie in one plane. Hence, the given statement is false and surfaces do not have to be coplanar.

For a surface to exist, it must have I closed-loop AND be coplanar.TrueFalse

For a surface to exist, it must have I closed-loop AND be coplanar.

True

False