Use the single-server drive-up bank teller operation referred to in Problems 1 and 2 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Question

Computers & Technology

Kamron Novak

9 November, 16:38

Use the single-server drive-up bank teller operation referred to in Problems 1 and 2 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

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Answers (1)

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Mylee Young · Answer 1

This question is incomplete, here's the complete question:

1. Willow Brook National Bank operates a drive-up teller window that allows customers to complete bank transactions without getting out of their cars. On weekday mornings, arrivals to the drive-up teller window occur at random, with an arrival rate of 24 customers per hour or 0.4 customers per minute. 3. Use the single-server drive-up bank teller operation referred to in Problems 1 to determine the following operating characteristics for the system: a.) The probability that no customers are in the system. b.) The average number of customers waiting. c.) The average number of customers in the system. d.) The average time a customer spends waiting. e.) The average time a customer spends in the system. f.) The probability that arriving customers will have to wait for service.

Explanation:

Arrival rate / lambda = 24 customers per hour or 0.4 customers per minute

Service rate / mu = 36 customers per hour or 0.6 customers per minute (from problem 1)

a.) The probability that no customers are in the system, P0 = 1 - / lambda / / mu

= 1 - (24/36) = 1/3 = 0.3333

b.) The average number of customers waiting

Lq = / lambda^2 / [/mu (/mu - / lambda) ] = 242 / [36 * (36 - 24) ] = 1.33

c.) The average number of customers in the system.

L = Lq + / lambda / / mu = 1.33 + (24/36) = 2

d.) The average time a customer spends waiting.

Wq = / lambda / [/mu (/mu - / lambda) ] = 24 / [36 * (36 - 24) ] = 0.0555 hr = 3.33 min

e.) The average time a customer spends in the system

W = Wq + 1//mu = 0.0555 + (1/36) = 0.0833 hr = 5 min

f.) The probability that arriving customers will have to wait for service.

= 1 - P0 = 1 - 0.3333 = 0.6667