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23 June, 23:20

In the planning stage, a sample proportion is estimated as pˆ = 81/90 = 0.90. Use this information to compute the minimum sample size n required to estimate p with 95% confidence if the desired margin of error E = 0.08. What happens to n if you decide to estimate p with 90% confidence?

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  1. 24 June, 00:21
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    In the planning stage, a sample proportion is estimated as formula = 81/90 = 0.90. Use this information to compute the minimum sample size n required to estimate p with 90% confidence if the desired margin of error E = 0.08. What happens to n if you decide to estimate p with 90% confidence?

    Confidence level

    90% = ?

    p=0.8

    Z value at 90% = 2.576

    d=0.08

    Sample size = (z2*p * (1-p)) / d2

    = (2.5762^2 * 0.9 * 0.2) / 0.122^2

    =1.19443968/0.0149

    =80.16

    The sample size required = 80.

    90% = ?

    Z value at 90% = 1.645

    d=0.12

    Sample size = (z2*p * (1-p)) / d2

    = (1.6452*0.8*0.2) / 0.122

    =30.06

    The sample size required = 31
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