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19 December, 17:29

Write a program which promptsuser to enter an integer value. Using while loop print the valuesfrom

zero up to the number enteredby the user.

• Enlist the odd numbers out of them

• Enlist the prime numbers out of odd number list and printtheir sum (add all the prime numbers)

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Answers (1)
  1. 19 December, 19:45
    0
    Answer:Following is the c+ + code for the problem:

    #include

    using namespace std;

    int main () {

    int number;

    cout<<"Enter the number"<
    cin>>number;

    int i=0, c=0, odd[500];

    while (i<=number) / /loop for printing the numbers form 0 to number.

    {

    cout<
    if (i%2!=0) / / storing in the odd array if the number is odd.

    {

    odd[c++]=i; //storing odd numbers ...

    }

    i++;

    }

    cout<
    i=0;

    cout<<"The odd numbers are "<
    while (i
    {

    cout<
    i++;

    }

    cout<
    i=0;

    int sum=0;

    while (i
    {

    int div=2;

    while (div
    {

    if (odd[i]%div==0)

    break;

    div++;

    }

    if (div==odd[i])

    {

    cout<
    sum+=odd[i]; //updating the sum ...

    }

    i++;

    }

    cout<
    return 0;

    }

    Output:

    Enter the number

    49

    0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49

    The odd numbers are

    1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49

    The prime numbers are

    3 5 7 11 13 17 19 23 29 31 37 41 43 47

    The sum of odd prime numbers is 326.

    Explanation:

    First I have printed the values from 0 to n and i have taken an array to store odd numbers. After that i have printed the odd values. And after that i have printed prime numbers among the odd numbers and their sum. These all operations are done using while loop.
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