Write 3 functions in the starter code below such that: add_to_dict () : takes a dictionary, a key, a value and adds the key, value pair to the dictionary. If key is already in dictionary then it displays the error message: "Error. Key already exists.". Returns dictionary. remove_from_dict () : takes a dictionary and key and removes the key from the dictionary. Returns dictionary. If no such key is found in the dictionary then it prints: "No such key exists in the dictionary.". Hint: Use try-except. find_key (dictt, key) : takes dictionary and key and prints value corresponding to the key from the dictionary: print ("Value: ", value). If key is not found, then prints: "Key not found." Hint: Use try-except

Question

Computers & Technology

Halle Olsen

26 March, 14:39

Write 3 functions in the starter code below such that: add_to_dict () : takes a dictionary, a key, a value and adds the key, value pair to the dictionary. If key is already in dictionary then it displays the error message: "Error. Key already exists.". Returns dictionary. remove_from_dict () : takes a dictionary and key and removes the key from the dictionary. Returns dictionary. If no such key is found in the dictionary then it prints: "No such key exists in the dictionary.". Hint: Use try-except. find_key (dictt, key) : takes dictionary and key and prints value corresponding to the key from the dictionary: print ("Value: ", value). If key is not found, then prints: "Key not found." Hint: Use try-except

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Answers (1)

Know the Answer?

Mohammed Chapman · Answer 1

Required code is given below:

Explanation:

def add_to_dict (dictt, key, value):

if key in dictt. keys ():

print ("Error. Key already exists.")

else:

dictt[key]=value

return dictt

def remove_from_dict (dictt, key):

try:

dictt[key]

dictt. pop (key, None)

return dictt

except KeyError:

print ("No such key exists in the dictionary.")

def find_key (dictt, key):

try:

value=dictt[key]

print ("Value: ", value)

except KeyError:

print ("Key not found.")