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9 March, 16:40

int) You are the head of a division of a big Silicon Valley company and have assigned one of your engineers, Jim, the job of devising an algorithm to sort through an English text of n words and convert it into an Esperanto document. Jim comes up with an algorithm which takes 2n2+2n bit operations to handle an input text with n words. Suppose the computers in your business can handle one bit operation every nanosecond (1 nanosecond = 10-9 seconds). How many nanoseconds would it take Jim's algorithm to convert a text with 10 wor

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  1. 9 March, 18:58
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    Correct option is E

    Explanation:

    a) 2n^2+2^n operations are required for a text with n words

    Thus, number of operations for a text with n=10 words is 2/cdot 10^2+2^{10}=1224 operation

    Each operation takes one nanosecond, so we need 1224 nanoseconds for Jim's algorithm

    b) If n=50, number of operations required is 2/cdot 50^2+2^{50}/approx 1.12589990681/times 10^{15}

    To amount of times required is 1.12589990681/times 10^{15} nanoseconds which is

    1125899.90685 seconds (we divided by 10^{9}

    As 1$day$=24$hours$=24/times 60$minutes$=24/times 60/times 60$seconds$

    The time in seconds, our algortihm runs is / frac{1125899.90685}{24/cdot 60/cdot 60}=13.0312 days

    Number of days is {/color{Red} 13.0312}

    c) In this case, computing order of number of years is more important than number of years itself

    We note that n=100 so that 2 (100) ^2+2^{100}/approx 1.267650600210/times 10^{30} operation (=time in nanosecond)

    Which is 1.267650600210/times 10^{21} seconds

    So that the time required is 1.4671881947/times 10^{16} days

    Each year comprises of 365 days so the number of years it takes is

    /frac{1.4671881947/times 10^{16}}{365}=4.0197/times 10^{13} years

    That is, 40.197/times 10^{12}=$Slightly more than $40$ trillion years$
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