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26 December, 11:27

If number is 20, what is printed to the console after this code is executed?

for (int i = 3; i < = number; i + = 2)

{

if (number % i = = 0)

{

System. out. println (i);

if (i = = number)

System. out. println ("special");

break;

}

}

a. 5

b. 5

5

special

c. 20

special

d. 5

special

e. 2

+1
Answers (1)
  1. 26 December, 13:08
    0
    Option a is the correct answer for the above question

    Explanation:

    The above question code has one for-loop which runs two times only for the value of number=20. It is because when the if-condition will true then the loop will be exit because it holds the break statement which exits the for-loop when the if-condition will be true. So when the first time 20 will divide by 3 then if-condition will fail, but when the 20 will be divide by the 5, then the if condition will be true and the 5 will be printed as output. Then the second if-condition will false because it will be true for the 20 value of i. Hence option a is the correct answer while the other is not correct because others will not hold the output of this code.
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