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4 April, 17:39

How to the inverse function of f (x) = x2 + 1, x>o

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  1. 4 April, 20:50
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    f (x) = x² + 1, x > 0

    y = x² + 1

    x = y² + 1

    x - 1 = y²

    √x - 1 = y

    √x - 1 = f (x), x > 1
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