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5 January, 03:29

A Pitot tube is mounted in the test section of a low-speed subsonic wind tunnel. The flow in the test section has a velocity, static pressure, and temperature of 150 mi/h, 1 atm, and 70∘F, respectively. Calculate the pressure measured by the Pitot tube.

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  1. 5 January, 04:03
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    Given Information:

    Static Pressure = P = 1 atm

    Temperature = T = 70°F

    Velocity = v = 150 mi/hr

    Required formation:

    Pressure of Pilot Tube = P₀ = ?

    Answer:

    Pressure of Pilot Tube = P₀ = 2172.36 lb/ft²

    Solution:

    Units Conversion:

    (1 atm = 2116.22 lb / ft²)

    Static Pressure = P = 1 atm = 2116.22 lb/ft²

    (1° F = 459.67° R)

    Temperature = T = 70°F = 70 + 459.67 = 529.67° R

    (1mi/hr = 1.467 ft/sec)

    Velocity = v = 150 mi/hr = 220 ft/sec

    Density of Test Section

    Density = ρ = P/RT

    Where R is the idea gas constant 1717 (ft-lbf/slug-°R)

    ρ = 2116.22/1717*529.67 = 0.00232 slug/ft³

    Pressure of Pilot Tube

    P₀ = P + (1/2) * ρ*v²

    P₀ = 2116.22 + (1/2) * 0.00232*220²

    P₀ = 2172.36 lb/ft²
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