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24 December, 19:37

Calculate the radius of gyration for a bar of rectangular cross section with thickness t and width w for bending in the direction of (a) the thickness, (b) the width, and (c) transverse to a diagonal.

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  1. 24 December, 21:18
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    a) R = sqrt (wt³/12wt)

    b) R=sqrt (tw³/12wt)

    c) R = sqrt (wt³/12xcos45xwt)

    Explanation:

    Thickness = t

    Width = w

    Length od diagonal = sqrt (t² + w²)

    Area of raectangle = A = tW

    Radius of gyration = r = sqrt (I/A)

    a)

    Moment of inertia in the direction of thickness I = w t³/12

    R = sqrt (wt³/12wt)

    b)

    Moment of inertia in the direction of width I = t w³/12

    R=sqrt (tw³/12wt)

    c)

    Moment of inertia in the direction of diagonal I = (w t³/12) cos 45 = (wt³/12) x 1/sqrt (2)

    R = sqrt (wt³/12xcos45xwt)
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