Ask Question
15 August, 20:22

A horse on the merry-go-round moves according to the equations r = 8 ft, u = (0.6t) rad, and z = (1.5 sin u) ft, where t is in seconds. Determine the cylindrical components of the velocity and acceleration of the horse when t = 4 s.

+1
Answers (1)
  1. 15 August, 23:09
    0
    velocity = 0.664 ft/s, acceleration = 0.365 ft/s²

    Explanation:

    z = 1.5 sin 0.6t

    angular velocity = dz/dt = d (1.5sin0.6t) / dt

    = 0.9cos0.6t

    at t=4

    =0.9cos (0.6*4)

    = - 0.664 ft/s

    Acceleration = dv/dt

    = d (0.9cos0.6t) / dt

    = - 0.54sin0.6t

    at t=4

    acceleration = - 0.54sin (0.6**4)

    = 0.365 ft/s²
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A horse on the merry-go-round moves according to the equations r = 8 ft, u = (0.6t) rad, and z = (1.5 sin u) ft, where t is in seconds. ...” in 📙 Engineering if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers