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30 March, 09:47

Two resistors of values 7.0 and 15.0 Ω are connected in parallel. This combination in turn is hooked in series with a 3.8 - Ω resistor and a 22.3-V battery. What is the current in the 3.8 - Ω resistor?

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  1. 30 March, 13:10
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    1.8A

    Explanation:

    Firstly, we need to find the effective resistance in the circuit.

    For the two parallel resistors, the effective resistance is;

    1/R = 1/7 + 1/15

    R = 8.57Ω

    Now let's connect it in series with the series resistor

    R = 8.57 + 3.8 = 12.37Ω

    This is the total effective resistance

    The total current is therefore

    22.3/8.57 = 1.8A

    This is also the current flowing through the 3.8 resistor since it is connected in series
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