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19 November, 10:54

For a turning operation, you have selected a high-speed steel (HSS) tool and turning a hot rolled free machining steel. Your depth of cut will be 0.105 in. The diameter of the workpiece is 1.00 in. a. Using a speed of 105 sfpm and a feed of 0.015, calculate the metal removal rate (MRR).

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  1. 19 November, 12:02
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    MRR = 1.984

    Explanation:

    Given that

    Depth of cut, d=0.105 in

    Diameter D = 1 in

    Speed V = 105 sfpm

    feed f = 0.015 ipr

    Now the metal removal rate given as

    MRR = 12 f V d

    d = depth of cut

    V = Speed

    f=Feed

    MRR = Metal removal rate

    By putting the values

    MRR = 12 f V d

    MRR = 12 x 0.015 x 105 x 0.105

    MRR = 1.984

    Therefore answer is -

    1.944
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