The driving force for fluid flow is the pressure difference, and a pump operates by raising the pressure of a fluid (by converting the mechanical shaft work to flow energy). A gasoline pump is measured to consume 3.8 kW of electric power when operating. If the pressure differential between the outlet and inlet of the pump is measured to be 7 kPa and the changes in velocity and elevation are negligible, determine the maximum possible volume flow rate of gasoline.

Question

Engineering

Jalen Irwin

3 January, 17:34

The driving force for fluid flow is the pressure difference, and a pump operates by raising the pressure of a fluid (by converting the mechanical shaft work to flow energy). A gasoline pump is measured to consume 3.8 kW of electric power when operating. If the pressure differential between the outlet and inlet of the pump is measured to be 7 kPa and the changes in velocity and elevation are negligible, determine the maximum possible volume flow rate of gasoline.

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Answers (1)

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Josephine Frost · Answer 1

The maximum possible volume flow of gasoline is 0.543 m^3/s

Explanation:

Power = pressure differential * volume flow rate

Power = 3.8 kW

Pressure differential = 7 kPa

Volume flow rate = power : pressure differential = 3.8 : 7 = 0.543 m^3/s