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2 March, 02:08

An aircraft is in a steady level turn at a flight speed of 200 ft/s and a turn rate about the local vertical of 5 deg/s. Thrust from the engine is along the flight direction. Given the weight of the aircraft as 50,000 lb and L/D of 10, determine the lift, drag and thrust required for the given equilibrium flight. Assume g = 32.2 ft/s^2

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  1. 2 March, 02:33
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    L = 50000 lb

    D = 5000 lb

    Explanation:

    To maintain a level flight the lift must equal the weight in magnitude.

    We know the weight is of 50000 lb, so the lift must be the same.

    L = W = 50000 lb

    The L/D ratio is 10 so

    10 = L/D

    D = L/10

    D = 50000/10 = 5000 lb

    To maintain steady speed the thrust must equal the drag, so

    T = D = 5000 lb
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