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17 June, 15:31

A. 02 kg of R-134a fills a 0.14-m3 weighted piston-cylinder device at a temperature of - 26.4°C. The container is now heated until the temperature is 100°C. Determine the final volume of R-134a. Use data from the refrigerant tables.

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  1. 17 June, 19:04
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    The answer is 0.06027 m³

    Explanation:

    Solution

    Given that:

    The first step to take is to determine the initial state of the volume for R-134a refrigerant

    Now,

    v₁ = V/m

    V = the volume of weighted piston cylinder device at the normal state

    m = the mass of the R-134a refrigerant

    Thus,

    We substitute the values 0.14 for V and 0.2 kg for m

    Which results in

    v₁ = 0.14/0.2

    v₁ = 0.7 m₃/kg

    The next step is to find the saturated pressure of the R-134a refrigerant from the temperature table of saturated refrigerant R-134a which is equivalent to the normal temperature of 26.4°C.

    Thus, by applying the method of interpolation we have the following

    P₁ = 101.73 - ((101.73-92.76) * (-26 - (-26.4) / -26 - (-28))

    P₁ = 99.936 kPa

    So,

    The refrigerant in the weighted piston-cylinder device is then heated until the temperature gets to a 100°C

    Hence, the temperature and pressure at a state of two becomes

    P₂ = 99.936 kPa

    T₂ = 100°C

    The next step is to determine the specific volume of the refrigerant R-134a at a final state from the super heated refrigerant R-134a which is equivalent to the pressure of 99.936 kPa

    v₂ = 0.30138 m³ / kg

    Now,

    we now calculate the final state of the weighted piston cylinder device

    V₂ = mv₂

    V₂ = 0.2 * 0.30138

    V₂ = 0.06027 m³

    Hence, the final volume of the weighted cylinder piston device is 0.06027 m³
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