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23 January, 05:15

Steam flows steadily through a turbine at a rate of 420 kg/min. The enthalpy of the steam decreases by 600 kJ/kg as it flows steadily through the turbine. If the power generated by the turbine is 4 MW, determine the rate of heat loss from the steam turbine [kW).

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  1. 23 January, 06:01
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    the rate of heat loss from the steam turbine is Q = 200 kW

    Explanation:

    From the first law of thermodynamics applied to open systems

    Q-W₀ = F * (ΔH + ΔK + ΔV)

    where

    Q = heat loss

    W₀ = power generated by the turbine

    F = mass flow

    ΔH = enthalpy change

    ΔK = kinetic energy change

    ΔV = potencial energy change

    If we neglect the changes in potential and kinetic energy compared with the change in enthalpy, then

    Q-W₀ = F*ΔH

    Q = F*ΔH + W₀

    replacing values

    Q = F*ΔH + W₀ = 420 kg/min * (-600 kJ/kg) * 1 min/60 s * 1 MW/1000 kW + 4 MW = - 0.2 MW = - 200 kW (negative sign comes from outflow of energy)
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