Ask Question
6 June, 11:49

A pipe 300 m long has a slope of 1 in 100 and tapers from 1.2 m diameter at the high end to 0.6 m diameter at the low end. Quantity of water flowing is 5400 liters per minute. If the pressure at the high end is 68.67 kPa, find the pressure at the low end. Neglect head loss.

+5
Answers (1)
  1. 6 June, 13:45
    0
    P = 98052.64 Pa or 98.05 kPa

    Explanation:

    Using Bernoulli's equation;

    P+rho*v^2/2 + rho*g*z = constant

    at high end;

    dia = 1.2 m

    flow, Q = 5400 L/min = 0.09 m^3/s

    therefore, velocity at the high end, v1 = Q/A = 0.09 / (pi () * (1.2/2) ^2) = 0.08 m/s

    pressure, P = 68.67 kPa

    Solving for elevation, z

    assume lower end is reference line. then higher end will be 'x' m high wrt to lower end.

    x = 300*sin (tan^-1 (1/100)) = 3 m

    that means higher end will be 3 m above with respect to lower end

    Similarly for lower end;

    dia = 0.6 m

    flow, Q = 5400 L/min = 0.09 m^3/s

    therefore, velocity at the high end, v2 = Q/A = 0.09 / (pi () * (0.6/2) ^2) = 0.318 m/s

    assume pressure, P

    z=0

    put all values in the formula, we get;

    68.67*10^3+1000*0.08^2/2 + 1000*9.81*3 = P+1000*0.318^2/2 + 0

    solving this, we get;

    P = 98052.64 Pa or 98.05 kPa
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A pipe 300 m long has a slope of 1 in 100 and tapers from 1.2 m diameter at the high end to 0.6 m diameter at the low end. Quantity of ...” in 📙 Engineering if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers