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1 July, 17:41

Same rule: If both players spend the same number of coins, player 2 gains 1 coin. Off-by-one rule: If the players do not spend the same number of coins and the positive difference between the number of coins spent by the two players is 1, player 2 is awarded 1 coin. Off-by-two rule: If the players do not spend the same number of coins and the positive difference between the number of coins spent by the two players is 2, player 1 is awarded 2 coins. The following is an example of a game played with a starting value of 10 coins and a game length of 5 rounds

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  1. 1 July, 21:00
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    Check the explanation

    Explanation:

    1 -

    public int getPlayer2Move (int round)

    {

    int result = 0;

    //If round is divided by 3

    if (round%3 = = 0) {

    result = 3;

    }

    //if round is not divided by 3 and is divided by 2

    else if (round%3! = 0 && round%2 = = 0) {

    result = 2;

    }

    //if round is not divided by 3 or 2

    else {

    result = 1;

    }

    return result;

    }

    2-

    public void playGame ()

    {

    //Initializing player 1 coins

    int player1Coins = startingCoins;

    //Initializing player 2 coins

    int player2Coins = startingCoins;

    for (int round = 1; round < = maxRounds; round++) {

    //if the player 1 or player 2 coins are less than 3

    if (player1Coins < 3 || player2Coins < 3) {

    break;

    }

    //The number of coins player 1 spends

    int player1Spends = getPlayer1Move ();

    //The number of coins player 2 spends

    int player2Spends = getPlayer2Move (round);

    //Remaining coins of player 1

    player1Coins - = player1Spends;

    //Remaining coins of player 2

    player2Coins - = player2Spends;

    //If player 2 spends the same number of coins as player 2 spends

    if (player1Spends = = player2Spends) {

    player2Coins + = 1;

    continue;

    }

    //positive difference between the number of coins spent by the two players

    int difference = Math. abs (player1Spends - player2Spends);

    //if difference is 1

    if (difference = = 1) {

    player2Coins + = 1;

    continue;

    }

    //If difference is 2

    if (difference = = 2) {

    player1Coins + = 2;

    continue;

    }

    }

    / / At the end of the game

    //If player 1 coins is equal to player two coins

    if (player1Coins = = player2Coins) {

    System. out. println ("tie game");

    }

    //If player 1 coins are greater than player 2 coins

    else if (player1Coins > player2Coins) {

    System. out. println ("player 1 wins");

    }

    //If player 2 coins is grater than player 2 coins

    else if (player1Coins < player2Coins) {

    System. out. println ("player 2 wins");

    }

    }
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