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30 May, 13:21

A treated aluminum plate is irradiated with G-1000 Wm2 while at a temperature of 400 K The plate is treated with a surface coating that provides an absorptivity of 0.14 and an emissivity of 0.76. Find:

(a) The radiosity, J, of the plate surface

(b) The net radiation heat flux at the top surface

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  1. 30 May, 16:22
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    (a) The radiosity, J, of the plate surface is 1343.2 W/m²

    (b) The net radiation heat flux at the top surface is 1863.2 W/m²

    Explanation:

    J = εσT⁴ + (1 - ε) G

    where;

    J is the radiosity of the plate surface

    ε is the emissivity

    σ is the stefan-Boltzmann constant

    T is the temperature of the surface

    G is the irradiance of the surface

    J = 0.76 x 5.67 x 10⁻⁸ x (400) ⁴ + (1 - 0.76) x 1000

    J = 1343.2 W/m²

    Part (b) net radiation heat flux at the top surface

    this is equivalent to sum of reflected and emitted heat.

    Rnet = G - (Rσ + Rt) + Rε

    Rnet = G + Rε - (Rσ + Rt)

    Rnet = G + εσT⁴ - (1 - ε) G

    Rnet = 1000 + 1103.2 - 240

    Rnet = 1863.2 W/m²

    Therefore, the net radiation heat flux at the top surface is 1863.2 W/m²
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