Determine the total condensation rate of water vapor onto the front surface of a vertical plate that is 10 mm high and 1 m in the horizontal direction. The plate is exposed to saturated steam at atmospheric pressure and is maintained at 75oC.

Q = 63,827.5 W

Explanation:

Given:-

- The dimensions of plate A = (10 mm x 1 m)

- The fluid comes at T_sat, 1 atm.

- The surface temperature, T_s = 75°C

Find:-

Determine the total condensation rate of water vapor onto the front surface of a vertical plate

Solution:-

- Assuming drop-wise condensation the heat transfer coefficient for water is given by Griffith's empirical relation for T_sat = 100°C.

h = 255,310 W / m^2. K

- The rate of condensation (Q) is given by Newton's cooling law:

Q = h*As * (T_sat - Ts)

Q = (255,310) * (0.01*1) * (100 - 75)

Q = 63,827.5 W

Q = 63,827.5 W

Explanation:

From the questions given, we recall the following,

The dimensions of vertical plate A = (10 mm x 1 m)

The fluid comes at T_sat, 1 atm.

The surface temperature pressure maintained T_s = 75°C

Thus we determine,

The total rate of condensation of water vapor onto the front surface of a vertical plate

Assuming drop-wise condensation the heat transfer coefficient for water is given by

Griffith's empirical relation for T_sat = 100°C.

Then

h = 255,310 W / m^2. K

The rate of condensation (Q) is stated by Newton's cooling law:

Q = h x As x (T_sat - Ts)

Q = (255,310) x (0.01 x 1) x (100 - 75)

Therefore

Q = 63,827.5 W