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20 November, 19:03

Example - a 100 kW, 60 Hz, 1175 rpm motor is coupled to a flywheel through a gearbox • the kinetic energy of the revolving components is 300 kJ at rated speed - the motor is plugged to a stop and allowed to run up to 1175 rpm in the reverse direction • calculate the energy dissipated in the rotor

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  1. 20 November, 21:48
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    1200KJ

    Explanation:

    The heat dissipated in the rotor while coming down from its running speed to zero, is equal to three times its running kinetic energy.

    P (rotor-loss) = 3 x K. E

    P = 3 x 300 = 900 KJ

    After coming to zero, the motor again goes back to running speed of 1175 rpm but in opposite direction. The KE in this case would be;

    KE = 300 KJ

    Since it is in opposite direction, it will also add up to rotor loss

    P (rotor loss) = 900 + 300 = 1200 KJ
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