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18 February, 04:02

How does kinetic energy affect the stopping distance of vehicle traveling at 30 mph compared to the same vehicle traveling at 60 mph

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  1. 18 February, 04:14
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    We have to determine the difference between the stopping distances of the vehicle traveling at 30 mph to the same vehicle traveling at 60 mph. Kinetic energy formula is: KE = 1/2 m v^2. - KE = - (Mi) m g d, where d stays for the stopping distance. Therefore: - 1/2 m v^2 = - (Mi) m g d. (we can divide both sides by - m); 1/2 v^2 = (Mi) g d; d = v^2 / 2 (Mi) g. The stopping distance is determined by the square of starting velocity and the effective coefficient of friction between the tires and the road (Mi). So d 1 = (30 ^2) / 2 (Mi) g = 450 / (mi) g; and: d 2 = (60^2) / 2 (Mi) g = 1800 / (Mi) g; d 1 : d 2 = 1/4; d 2 = 4 d 1. Answer: It affects that the second stopping distance becomes 4 times greater than the first.
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