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8 October, 04:09

Given any triangle ABC with corresponding side lengths a, b, c the law of cosines states:? Can someone explain to me how I get this

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  1. 8 October, 06:10
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    As per convention:

    - the angle at A is named A, the angle at B is named B, and the angle at C is named C

    - the side of leght a is the side opposed to A, the side of length b is opposed to B, and the side of length c is opposed to C.

    Now just state the law of cosines:

    c^2 = a^2 + b^2 - 2ab cos (C)

    Also, a^2 = c^2 + b^2 - 2bc cos (A)

    And, b^2 = a^2 + c^2 - 2ac cos (B)
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