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1 October, 15:28

On a winter day the temperature drops from - 15°c to - 25°c overnight. if a pan sitting outside contains 0.40 kg of ice, how much heat is removed from the ice for this temperature change?

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  1. 1 October, 18:42
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    The problem can be solve using the formula:

    q = m cp dt

    where q is the heat removed

    cp is the heat capacity of the material (2.108 kJ/kg C for ice)

    dt is the change temperature

    q = (0.40 kg) (2.108 kj/kg C) (-25 - (-15) C)

    q = - 8.432 kj

    the negative sign indicates that it is removed
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