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16 April, 14:07

In ΔJKL, solve for x. Triangle JKL where angle K is a right angle. KL measures 34. JL measures x. Angle L measures 27 degrees.

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  1. 16 April, 16:28
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    J = 27°

    K = 90°

    L = 90° - 27° = 63°

    x is the hypotenuse.

    34 is the short leg or opposite

    the long leg is the adjacent

    sine Θ = opposite / hypotenuse

    sine 27° = 34 / x

    sin (27°) * x = 34

    x = 34 / sin (27°)

    x = 34 / 0.45399

    x = 74.89

    Answer is B.) 74.89
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