The flame temperature in an automobile engine is 1699 °f, and the exhaust is emitted at 229 °f. what is the carnot efficiency of the engine?

Solution:

η = Efficiency; T (hot) = Temperature of the Hot source; T (cold) = Temperature of the Cold Sink;

η = 1 - {T (cold) / T (hot) }

η = 1 - {229 / 1699}

η = 0.6809748595199822 x 100

η = 68.09 %

The answer is 68.09 %, you can use the Carnot Thermal efficiency Calculator in the Internet.