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Mathematics
Elise
9 February, 16:59
Verify
cos^4x-sin^4x=cos2x
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Darren Mendez
9 February, 17:09
0
A^2 - b^2 = (a - b) (a + b);
cos^4x-sin^4x = (cos^2x + sin^2x) (cos^2x - sin^2x) = 1 * cos2x = co2x.
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