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17 July, 00:28

How many liters of water should be added to 18 liters of 14% bleach solution so that the remaining solutions contains only 10% bleach

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Answers (2)
  1. 17 July, 01:24
    0
    We must take that the 14 % is volumentric. This is we will use only volumetric measures.

    From the original solution you can find the quantity of bleach.

    Original solution: 18 liters * [14 liters of bleach / 100 liters of solution] = 2.52 liters.

    Now you know that those 2.52 liters shall represent the 10% of the new solution, after having added x liters of water. Then:

    [2.52 liters of bleach] / [volume of solution] = 10% = 0.1

    => volume of solution = 2.52 liters / 0.1 = 25.2 liters of solution.

    That tells you that you have to add 25.2 liters - 18 liters = 7.2 liters of water.

    Check that in that case you will have:

    2.52 liters of bleach

    18 liters of the original solution

    7.2 liters of new water added to the original solution.

    2.52 liters of bleach / [18 + 7.2] liters of solution = 0.1 = 10%.

    Then, the answer is: 7.2 liters of water should be added.
  2. 17 July, 03:35
    0
    X - liters of water (0% bleach);

    (18 + x) * 0.1 = 18 * 0.14 + x * 0

    1.8 + 0.1 x = 2.52 + 0

    0.1 x = 2.52 - 1.8

    0.1 x = 0.72

    x = 0.72 : 0.1

    x = 7.2 liters

    Answer: 7.2 liters of water should be added.
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