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29 January, 00:40

Rose counted her money and found that her 25 coins which were nickels, dimes, and quarters were worth $3.20. the number of dimes exceeded the number of nickels by 4. how many coins of each kind did she have?

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  1. 29 January, 02:42
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    N = number of nickles

    D = number of dimes = N+4

    Q = number of quarters

    = 25-N-D

    = 25-N - (N+4)

    = 21 - (2N)

    Add the coins to get $3.20

    (N*$0.05) + (D*$0.10) + (Q*$0.25) = $3.20

    Expressing D and Q in terms of N:

    (N*$0.05) + ((N+4) * $0.10) + (21-2N) * $0.25=$3.20

    Solve for N. Then plug N into the equations for D and Q
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