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26 May, 06:36

What is the value of the summation ∑i=14 (2i+6i2)

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  1. 26 May, 08:12
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    You need to know the following:

    sigma (i) = 1/2 * i * (i+1)

    sigma (i^2) = 1/6 * i * (i+1) * (2i+1)

    Therefore, the answer should be 14 (i (i+1) + i * (i+1) * (2i+1)) = 14i (i+1) (2i+2) = 28i (i+1) ^2
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