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19 May, 19:03

State the value of the discriminant for each equation. Then determine the number of real solutions of the equation.

1) 0.5x^2-2x=-2

2) 2x^2-5x+20=0

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  1. 19 May, 21:49
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    1) b^2 - 4ac = (-2) ^2 - 4 * (0.5) * 2 = 4 - 4 = 0;

    2) b^2 - 4ac = (-5) ^2 - 4*2*20 = 25 - 160 = - 135;
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