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29 March, 17:39

Find a polynomial of degree 2 with real number coefficients and zero 3-2i

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  1. 29 March, 20:21
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    Complex roots occur as conjugates so the other root is 3 + 2i

    so we have the factored form

    (x - (3 - 2i) (x - (3 + 2i)

    = (x - 3 + 2i) (x - 3 - 2i)

    = x^2 - 3x - 2ix - 3x + 9 + 6i + 2ix - 6i - 4i^2

    = x^2 - 6x + 9 + 4

    = x^2 - 6x + 13 Answer
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