These triangles are similar. find the missing length, h.

7*6*7/2. 1*h*1/2

If I understand the question correctly, the sides of one triangle

are 7 ... 6 ... and 7/2, and the sides of the second triangle

are 1 ... h ... and 1/2, and the triangles are similar.

OK. The ratio of the first pair of sides is 7 / 1 = 7, and the

ratio of the second pair of sides is (7/2) / (1/2) = 7, so

I'm pretty sure the ratio of the missing pair of sides is also 7.

h = 6/7