Pranav made a nut mixture that contains 82% peanuts by mixing 6kg of mixed nuts with 9kg of peanuts. The mixed nuts contained what percent peanuts?

Ok so

82%=82/100=0.82

82% of all = peanuts

total=6+9=15kg

all=15

0.82 times 15=peanuts

12.3=peanuts

12.3kg of peanuts total

9kgpeanuts+xkgpeanuts (inmixednuts) = 12.3

subtract 9 from both sides

xkgpeanuts=3.3kg

3.3/9=x%

x%=x/100

3.3/9=x/100

1.1/3=x/100

multiply both sides by 300

110=3x

divide both sides by 3

36.6666=x

36.6666% is answer

aprox 37%