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22 November, 19:57

In the diagram below of right triangle ACB, altitude CD is drawn by hypotenuse AB. if AB = 36 and AC = 12, what is the length of AD?

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  1. 22 November, 21:24
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    36 squared + 12 squared = AD squared

    1296 + 144 = AD squared

    square root of 1440 = AD

    37.95
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