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Mathematics
Karter
31 May, 01:11
Integral of 1 / (x^2sqrt (4x+1)) ?
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Kahlua
31 May, 03:04
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Integral of 1 / (x^2sqrt (4x+1)) = 4tanh^-1 (sqrt (4x + 1)) - sqrt (4x + 1) / x + c
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