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29 January, 23:25

Suppose you have a wallet with $5 bills, $10 bills, and $20 bills. If the probability of picking a $20 bill is 4/15, and the probability of picking a $20 bill is 4/15, and the probability of picking a $5 bill is 1/3, what is the probability of picking a $20 bill?

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  1. 30 January, 02:43
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    The question does not make any sense. The probability of a 20 bill has already been given.

    Given:

    $5 bills

    $10 bills

    $20 bills

    probability of $20 is 4/15

    probability of $5 is 1/3

    numerator is the number of events

    denominator is the number of outcomes

    the missing probability is of the $10 bill.

    4/15 + 1/3 + x = 1 or 15/15

    $5 bill = 1/3 x 5/5 = 5/15

    15/15 - 4/15 - 5/15 = (15-4-5) / 15 = (15-9) / 15 = 6/15 = 2/5

    the probability of $10 is 2/5
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