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30 June, 15:55

The equation of the hyperbola with foci (5, 0), (-5, 0) and vertices (4, 0), (-4, 0) is:

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  1. 30 June, 19:23
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    y²/3² - x²/4² = 1, because two types of hyperbolas, one where a line drawn through its vertices and foci is horizontal, and one where a line drawn through its vertices and foci is vertical.
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