The altitude to the hypotenuse of a right triangle divides the hypotenuse into two segments measuring 11 centimeters and 5 centimeters. to the nearest tenth, what is the length of the shorter leg of the triangle?

A^2 = x^2 - 5^2 where a = altitude, x=shorter leg and y=longer leg.

a^2 = y^2 + 11^2

x^2 - 5^2 = y^2 - 11^2 ... (1)

Also consider the whole triangle:

x^2 + y^2 = 16^2 ... (2)

x^2 - y^2 = - 96 ... (3) (from equation (1))

adding 2 x^2 = 256 + - 96 = 160

x^2 = 80

x = sqrt80

= 8.94 to nearest hundredth