Find the difference 5/x^2-6x - 1/x^2-36

the difference of x/25x-125-1/x^2-5x (x/25x-125) - 1 / (x^2-5x) = x / 25 (x-5) - 1 / x (x-5) = (1/x-5) (x/25-1/x) factorized by 1/x-5, and (1/x-5) (x/25-1/x) = (1/x-5) (x²-25/25x) = (1/x-5) [ (x-5) (x+5) / 25x] = (x+5) / 25x simplified by x-5so the final answer is x/25x-125-1/x^2-5x = (x+5) / 25x

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