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15 June, 04:09

From the top of a vertical cliff 40 m high, the angle of depression of an object that is level with the base of the cliff is 34 degrees. how far is the object from the base of the cliff?

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  1. 15 June, 04:38
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    You need to use the pathagoreum therum (sorry if I spelled that wrong) and do 40^2+34^2 which is 2756 then find the square root of 2756 which is 52.5 which is the answer
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