The mean output of a certain type of amplifier is 117 watts with a variance of 100. if 42 amplifiers are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 3.3 watts? round your answer to four decimal places.

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Mathematics

Fox

4 September, 19:00

The mean output of a certain type of amplifier is 117 watts with a variance of 100. if 42 amplifiers are sampled, what is the probability that the mean of the sample would differ from the population mean by less than 3.3 watts? round your answer to four decimal places.

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Jaden Brock · Answer 1

The probability that mean sample will differ from population mean by 3.3 watts will be given as follows:

P (113.7
z-score is given by:

z = (x-μ) / σ

but

n=42

hence:

σ/√n

100/√42=15.43

thus

when x=113.7

z = (-3) / 15.43

z=-0.1944

P (z<-0.1944) = 0.4247

when x=120.3

z=3.3/15.43

z=0.214

P (z<0.214) = 0.5832

hence:

P (113.7