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1 July, 14:31

A body travels 10 meters during the first 5 seconds of its travel, and it travels a total of 30 meters over the first 10 seconds of its travel. What is its average speed during the time from t = 5 seconds to t = 10 seconds?

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Answers (2)
  1. 1 July, 14:57
    0
    The answer is 4 m/s.

    In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).

    The relation of speed (v), distance (d), and time (t) can be expressed as:

    v = d/t

    We need to calculate the speed of the second 5 seconds of the travel:

    d = 20 m (total 30 meters - first 10 meters)

    t = 5 s (time from t = 5 seconds to t = 10 seconds)

    Thus:

    v = 20m / 5s = 4 m/s
  2. 1 July, 15:11
    0
    A body travels 10 meters during the first 5 seconds of its travel, and a total of 30 meters over the first 10 seconds of its travel

    20miles / 5sec = 4miles / sec would be the average speed for the last 20 min
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